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About Seymour
Seymour is a city in Township of Walnut, Wayne County, Iowa, United States.
| Population | 696 |
| Time zone | America/Chicago |
| Elevation | 323 |
| Open Seymour in Google Maps | |
| #data | latitude | longitude |
|---|---|---|
| Geographic coordinates | 40.6825100 | -93.1210400 |